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Jul 6, 2015 at 12:37 comment added Andy aka I'd reckon on maybe 8 to 10 watts and a heat sink will be required if discharging for a more than a few seconds. Driving the FET is PWM mode is irrelevant unless you want to apply a pulsing load.
Jul 6, 2015 at 12:20 comment added yiipmann So if i use a N channel Power Transistor like This One it would mean that i would be dissipating (@40A) around 1600x4.3mOhm = 7 Watts of power in the transistor right ? Dissipation is okay with me as my main aim IS to dissipate power. But what about heating of the transistor ? would i need to use a heat sink for that ? or shall i drive my power transistor in PWM mode ?
Jun 18, 2015 at 12:48 comment added Andy aka If you are drawing 50A from the "boosted" output then the current taken from the battery is going to be more. If you haven't designed the buck converter correctly (to cope with +50A in reverse boost mode) then the whole implementation is going to fail. I have presumed that your buck converter is designed by you (hence your previous question about the IR device) and that because you are designing the buck, implementing a power rail switch is relatively more simple. Are you not designing the buck/boost circuit? Basically, any MOSFET used as the synchro FET will have to cope with currents >50A.
Jun 18, 2015 at 12:19 comment added yiipmann Your idea seems very helpful. But i think as WhatRoughBeast said in the above post that i will have to take care of other things too while implementing this technique(PCB tracing for e.g), i think i should not opt it as i have never ever done pcb designing before and it would be my first time. So may be i should go for the Relays.
Jun 16, 2015 at 13:56 history answered Andy aka CC BY-SA 3.0