Timeline for Capacitor bank for smoothing full-wave rectification output
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 28, 2016 at 12:44 | answer | added | Autistic | timeline score: 0 | |
| Jun 28, 2016 at 11:47 | comment | added | JimmyB | Quick math: For 180A, 120Hz, 1V ripple, you'd need about 180A/(120Hz*1V) = 1.5F. At about 20V, the ESR must be an order of magnitude or two below 20V/180A~0.1Ohm. | |
| Jun 28, 2016 at 5:05 | answer | added | Neil_UK | timeline score: 2 | |
| Jun 28, 2016 at 1:23 | comment | added | Mark | Do you have three-phase available? The ripple before filtering is a lot less with full-wave rectified three-phase. | |
| Jun 28, 2016 at 0:51 | history | edited | Jeremy Adams | CC BY-SA 3.0 | Added details and questions about what could be done to solve my problem |
| Jun 28, 2016 at 0:32 | comment | added | user2943160 | At 180A, you will likely need impractically large amount of bypass capacitance if you need a stable voltage at the output of the device. An offline switching supply would be recommended, but designing a 180A, 15-24V supply is not a small task. | |
| Jun 28, 2016 at 0:31 | history | edited | Jeremy Adams | CC BY-SA 3.0 | I added additional information on the background of my circuit. |
| Jun 28, 2016 at 0:05 | comment | added | Transistor | (1) What is this power supply for? (2) Why does it need to be smoothed? (3) Is three-phase power available? Put the information in the question and not in the comments. Welcome to EE.SE. | |
| Jun 27, 2016 at 23:59 | review | First posts | |||
| Jun 28, 2016 at 0:32 | |||||
| Jun 27, 2016 at 23:56 | history | asked | Jeremy Adams | CC BY-SA 3.0 |