Timeline for Use floating values in VHDL code
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
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| Jan 21, 2019 at 12:32 | comment | added | ArtificialSoul | @SolomonSlow Just a slight mistake: 10.5 mA is 10500 µA not 1050µA, that'd be 1.05 mA. | |
| Mar 15, 2018 at 16:10 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Feb 13, 2018 at 0:16 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Dec 12, 2017 at 5:52 | answer | added | user169703 | timeline score: 1 | |
| Dec 11, 2017 at 18:38 | comment | added | user16324 | Rather than hacking things to make integers fit (which is viable but maybe ugly) you can use the synthesisable fixed point (or floating point) libraries in VHDL-2008. If it's simulation only, just declare subtype Voltage_level is real range -5.5 to 5.5; | |
| Dec 11, 2017 at 18:21 | comment | added | Solomon Slow | 10.5 mA is 1050 µA. Voilà! An integer. Or, you might choose to think of it as 21 half milliamperes, or 42 quarter milliamperes. Also, both integers. The solution to your problem could just be a matter of choosing the right scale factor. | |
| Dec 11, 2017 at 17:56 | history | asked | bojee | CC BY-SA 3.0 |