I am trying to do a nodal analysis of this circuit.

and I need to do this by nodal analysis only.

I need to find \$ i_1 \$, \$ i_2 \$ and \$ i_3 \$.

I have found that

\$ i_1 = \frac{V_B - V_A}{R_1} = \frac{40 - (-15)}{10} = \frac{55}{10} = 5.5 A \$

\$ i_3 = \frac{V_A}{R_2 + R_3} = \frac{-15}{5 + 25} = \frac{-15}{30} = -0.5 A \$

Both these value are correct, according to the simulator.

But this is the problem:

\$ i_2 = i_1 + i_3 = 5.5 + (-0.5) = 5 A \$

But the simulator says 6A.

What is the correct way to approach that?

I am trying to do a nodal analysis of this circuit.

and I need to do this by nodal analysis only.

I need to find \$ i_1 \$, \$ i_2 \$ and \$ i_3 \$.

I have found that

\$ i_1 = \frac{V_B - V_A}{R_1} = \frac{40 - (-15)}{10} = \frac{55}{10} = 5.5 A \$

\$ i_3 = \frac{V_A}{R_2 + R_3} = \frac{-15}{5 + 25} = \frac{-15}{30} = -0.5 A \$

Both these value are correct, according to the simulator.

But this is the problem:

\$ i_2 = i_1 + i_3 = 5.5 + (-0.5) = 5 A \$

But the simulator says -6A.

What is the correct way to approach that?