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Timeline for Latching power with LDO enable pin

Current License: CC BY-SA 4.0

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Jun 16, 2019 at 19:53 comment added Elliot Alderson On second thought, the leakage through the diodes will not be a problem. Don't forget to add the capacitors as recommended in the datasheet....they keep the regulator from oscillating.
Jun 16, 2019 at 16:40 comment added rea104 Apologies for that! Found out after this interaction with you. I edit the question to include that information in case is useful for someone else. Thanks a lot for your comments!
Jun 16, 2019 at 16:18 comment added Elliot Alderson Ah. It would have been considerate to those of us reading the question to provide that information up front, in the form of a link to the datasheet. Now the question is, how much current leaks through the diodes and what voltage does it produce across a 3 megohm resistor?
Jun 16, 2019 at 15:16 comment added rea104 It pulls the SENSE pin LOW. For the EN pin, the LDO has an internal pull-down resistor of 3M.
Jun 16, 2019 at 14:45 comment added Elliot Alderson R1 can not pull EN low because D1 prevents current flow in the necessary direction. If you want R1 to pull EN low then you must move it to the other side of D1, connecting R1 directly to the EN pin.
Jun 16, 2019 at 8:30 comment added rea104 Dc-dc converter you mean a buck-boost converter? I was trying to avoid it due to complexity reasons. In any case, those also present an EN pin that can be used in the same manner. Setting the micro ENABLE pin to LOW will not set the voltage at LDO EN to 0 and thus, turn it off? I checked and above 1.5V is considererd HIGH in the LDO EN, so 2.6V should be enough. I don't expect any problem on the input pin for the micro (very low current with the 10k R). R1 is there as a pull-down resistor, to ensure a LOW reading when the push-button is open. I'm new in electronics, thanks a ton!
Jun 15, 2019 at 19:24 history answered Elliot Alderson CC BY-SA 4.0