Timeline for Transimpedance Amplifier Gain Analysis
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 13, 2019 at 16:07 | vote | accept | BestQualityVacuum | ||
| Nov 7, 2019 at 22:19 | comment | added | BestQualityVacuum | Thanks again. If you don't mind me asking, when compared to how I was doing the calculations, the PDF went about it a different way, keeping the input signal as a current source whereas I used a source transformation to turn it into a voltage source. The transfer function for the closed-loop gain look really different, but why is that? Modeling the actual closed loop gain Av like shown above, I assumed that the open-loop was a logarithmic function, not like how they had it in equation 1. With that being the case, should the closed loop gain have the same shape as the open loop gain? | |
| Nov 7, 2019 at 20:15 | comment | added | Voltage Spike♦ | They are simply summing up all the currents going in and out of the node Vi. There are only four pathways: the current source, the capacitor Ci , the resisitor Rf and the capacitor Cf. If you find the current through all those points and sum them up, you get equation 2 | |
| Nov 7, 2019 at 20:08 | comment | added | BestQualityVacuum | Thanks for your reply and the link. One question though, for equation 2 in the link, why are the currents summed up as they are? Given the node at Vi (or V1?), how is the author envisioning the currents leaving/entering the node? Are they thinking that the current 'sources' are from Ci and (Vo-Vi)/Zf? | |
| Nov 7, 2019 at 17:38 | history | edited | Voltage Spike♦ | CC BY-SA 4.0 | added 54 characters in body |
| Nov 7, 2019 at 16:48 | history | edited | Voltage Spike♦ | CC BY-SA 4.0 | added 65 characters in body |
| Nov 7, 2019 at 16:27 | history | answered | Voltage Spike♦ | CC BY-SA 4.0 |