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Apr 14, 2020 at 11:36 vote accept Kinka-Byo
Apr 14, 2020 at 2:48 comment added Kinka-Byo Maybe I have got it: it is basically due to the fact that E field is not uniform in each plane wavefront, but it has a wave behaviour which changes its direction along that waveform. So, in few words, can we say it is due to the fact that in waveguides we have non uniform plane waves?
Apr 13, 2020 at 12:39 comment added Kinka-Byo For "modes with more than one half-wave width" do you mean that the waveguide dimensions is greater than lambda/2?
Apr 13, 2020 at 12:13 comment added Marcus Müller read the sentence twice: "at any given time and point".
Apr 13, 2020 at 12:12 comment added Kinka-Byo Thank for your answer. It is more clear now, but I do not understand what you mean with the sentence "In free-space propagation, that's easy: at any given time and point, a plane wavefront will have exactly one direction of the E-field". In case of Elliptical polarization, the direction of E rotates in time, so it changes, so what do you mean with that statement? Moreover, I do not understand why this concept does not work for modes woth more than one half-wave width.
Apr 13, 2020 at 11:59 history answered Marcus Müller CC BY-SA 4.0