Timeline for Voltage across capacitor - pulse 2a
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 25, 2020 at 15:26 | vote | accept | CommunityBot | ||
| Apr 25, 2020 at 15:25 | comment | added | user220456 | Thank you for the suggestion. | |
| Apr 25, 2020 at 15:22 | comment | added | rpm2718 | @Newbie My advice is not to try to compute the capacitor voltage with the pulse you have, but first do the worst-case scenario, which is V1 steps instantaneously to 100 Volts. Then you can use the formula you used, except with E=100 Volts to find out how much voltage you are adding to the cap as a function of time ,beyond the Uo=14V. If you do this, you find that in the first 50 us, the cap stays below 35 Volts the whole time from 0 to 50 us. So then you are done! Your cap is safe, and you don't need more precision. You can stop at 50 us because your actual V1 pulse has come below 35V. | |
| Apr 25, 2020 at 15:08 | comment | added | user220456 | Thank you for the answer. I understand that the pulse application is not instantaneous. It gradually rises. But how would I compute without this formula? Could you help me with how would your computation method for this? And please also help on how to calculate the maximum power of a single pulse. I understand to get the power, we need to integrate the area under the curve. But how to do that calculation. | |
| Apr 24, 2020 at 20:26 | review | First posts | |||
| Apr 24, 2020 at 23:37 | |||||
| Apr 24, 2020 at 20:24 | history | answered | rpm2718 | CC BY-SA 4.0 |