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May 11 at 13:28 vote accept VALKYRIEiSr
May 11 at 13:28 vote accept VALKYRIEiSr
May 11 at 13:28
May 11 at 10:03 comment added Justme @VALKYRIEiSr Exactly - there is an RC circuit, but all resistors simply obey Ohm's law, current is defined only by resistance and voltage over the resistor. But the capacitor defines the voltage over resistor in an RC series circuit, because the capacitor voltage changes based on the charge it stores, and how the voltage changes depends on the current, and the current in turn is defined by the resistance, but anyway the phase shift in the resistor is caused by capacitor and the phase of resistor voltage is shifted compared to source voltage, but current and voltage in resistor has no shift.
May 11 at 8:51 comment added VALKYRIEiSr @Justme But if this was an RC circuit, where R would be the load. Althought I understand you wouldnt be driving something like a Heater through a RC circuit, this is a purely hypothetical scenario, because I dont understand how the load would respond in such a case.
May 11 at 8:06 comment added Justme @VALKYRIEiSr Such a scenario cannot happen, because in a purely resistive element, current and voltage are always in phase as there is no reactive elements that could shift the phase.
May 11 at 7:00 comment added VALKYRIEiSr What if you took a purely resistive load (lets say its a heater), and the current going through was leading the voltage. there will be a specific instant where the voltage is positive but the current is negative. So the power comes out to be negative. how does the heater behave at that instant where power is negative? technically since there is a current flowing through, it should generate heat. However, the negative sign begs to differ.
May 10 at 11:00 comment added periblepsis I think the questioner is more mathy than electronic in view. Probably wants the math. For example, the complex domain version of Ohm's Law? That said, I really like your answer, too. So I don't care, +1 anyway.
May 10 at 10:46 history answered Justme CC BY-SA 4.0