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Aug 14 at 6:28 comment added ai_ch this is exactly what I was looking for. In tina, I was not able to measure VF4 and use it as an voltage source with zero output impedance again as you did above. Thank you very much!
Aug 7 at 16:37 vote accept ai_ch
Aug 7 at 16:00 history edited Math Keeps Me Busy CC BY-SA 4.0
Warning re assumptions
Aug 7 at 15:35 history edited Math Keeps Me Busy CC BY-SA 4.0
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Aug 7 at 15:25 history edited Math Keeps Me Busy CC BY-SA 4.0
I had interpreted the question incorrectly.
Aug 7 at 14:02 comment added ai_ch in short: I only expect the two circuits I have shown above to be equivalent if a different voltage source is used, the second one having the unloaded output from the first one as a voltage source
Aug 7 at 13:51 comment added ai_ch Thanks for your very extensive answer. Maybe I've phrased my question wrong. For thevenin's equivalent source you need an internal resistance (here internal impedance) and a equivalent voltage source. My question was if the two circuits produce the same load behaviour, when in simulation I add the measured voltage VF4 as an input voltage to the second circuits voltage source (in DC circuits, this would be a voltage divider with a load on it). Yes, about the frequency behaviour I'm fully aware, but if I insert a capacitor in simulation it already is an impedance in the spice equations, isntit?
Aug 7 at 13:32 history edited Math Keeps Me Busy CC BY-SA 4.0
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Aug 7 at 13:20 history edited Math Keeps Me Busy CC BY-SA 4.0
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Aug 7 at 13:10 history edited Math Keeps Me Busy CC BY-SA 4.0
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Aug 7 at 12:51 history edited Math Keeps Me Busy CC BY-SA 4.0
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Aug 7 at 12:41 history answered Math Keeps Me Busy CC BY-SA 4.0