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Oct 23 at 10:16 comment added Ben Shaines Oh that is how I solved this, thanks :)
Oct 23 at 10:03 comment added Eric Towers @BenShaines : That is "if the least significant bit of X is 0, return X with its least significant bit set to 1, else return X+2 with its least significant bit set to zero."
Oct 23 at 7:13 comment added Ben Shaines Hi, sorry, didn't really understand what you wrote. But I already got answer to my question, so thanks though :)
Oct 23 at 0:47 history answered gnasher729 CC BY-SA 4.0