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Dec 14, 2023 at 23:35 vote accept qodeninja
Jun 22, 2017 at 0:01 answer added Leftium timeline score: 1
Jun 21, 2017 at 18:29 comment added Applekini I'm not sure if this is correct so I'll be posting this as a comment. Try this: matrix.identity();, matrix.scale(sqrt(2) / 2, sqrt(2) / 4, 1);, matrix.rotate(0, 0, 1, -45); //degrees, matrix.inverse(); in that order. Then you just multiply your position vector with that matrix (x, y).multiply(matrix);. The result of the final calculation should be your coordinates in iso space.
Jun 21, 2017 at 18:28 answer added Bálint timeline score: 2
Jun 21, 2017 at 18:09 history edited qodeninja CC BY-SA 3.0
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Jun 21, 2017 at 17:52 history edited qodeninja CC BY-SA 3.0
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Jun 21, 2017 at 17:46 review First posts
Jun 21, 2017 at 18:23
Jun 21, 2017 at 17:45 history asked qodeninja CC BY-SA 3.0