4
\$\begingroup\$

Problem:

I am using Skyrim Creation Kit to create a very simple mod. I want the mod to make one NPC follow another NPC. My first problem is that I am not really 100% sure where to start. The second problem is which functions I should use. I have been reading the documentation at www.creationkit.com. In other words:

LOOP: { // move Bob to Mike's current position with speed of 0.5 (npc_Bob.moveToPosition( npc_Mike.getPos(), 0.5 ) } // end loop

My Attempt:

I tried making a quest but to no avail. So then I made 2 custom actors (member and leader) and I put this script in member:

Scriptname NpcFollowNpc extends ObjectReference //***put a loop once you get this part working // moves member to leader with speed of 0.5 member.PathToReference(leader, 0.5)

but it didn't compile. I don't really know if this is the right way to implement what I want. I know how to code and make algorithms and a bunch of that computer science stuff, but I don't know how to move the actor member to the location of actor leader in Skyrim and loop it while the actor leader is alive.

Any ideas how I could go about doing this? thanks for any help/feedback!

\$\endgroup\$

1 Answer 1

Reset to default
1
\$\begingroup\$

As stated in this forum, you will need to Spawn a path point, attach it to an NPC. Then press U with the pathpoint selected to open the parameters. In the first text field, the one called Type, replace "Stand" with whatever (has to be written with a capital letter)

\$\endgroup\$
3
  • \$\begingroup\$ That's an interesting method. I actually used a different approach - I will post on here later, but basically I assigned a custom package (that used the Follow Package Template) to an actor. More info here. \$\endgroup\$ Commented Nov 1, 2017 at 22:24
  • 1
    \$\begingroup\$ @Ibrahim to be honest, I know little on Skyrim modding. I just had found the forum and put some of it's knowledge and my own into the answer. :) \$\endgroup\$ Commented Nov 1, 2017 at 23:30
  • \$\begingroup\$ I appreciate your input! I did not think of the way you suggested so I learned something new. \$\endgroup\$ Commented Nov 1, 2017 at 23:33

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.