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- 1If the accuracy goal is related to display on Google Maps, then Google's accuracy may compound your problem (see this blog post, for example, which finds a ~10m error).Erica– Erica2014-07-22 12:49:13 +00:00Commented Jul 22, 2014 at 12:49
- Hm very good point... unfortunately I don't have time to redesign the system I'm using so I'll have to rely on it for now. I was already not happy about using Google Maps (note that my equations are based on x-y coordinates, that's what I was planning on using for display) but I've been forced to go that direction for the moment.thanby– thanby2014-07-22 13:24:16 +00:00Commented Jul 22, 2014 at 13:24
- 2Actually thinking about it more, you may be OK, since you're going to be measuring distances from a position derived from Google Maps. The point would be ~10m inaccurate with respect to real-world location, but should be acceptably accurate with respect to photo-of-world location.Erica– Erica2014-07-22 13:46:25 +00:00Commented Jul 22, 2014 at 13:46
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