Solved

Author: nazmusweb-coding

Online platform problem solving/beecrowd/BEGINNER/.vscode/settings.json

@@ -0,0 +1,5 @@
+{
+ "files.associations": {
+ "P_1052.C": "cpp"
+ }
+}

Online platform problem solving/beecrowd/BEGINNER/a.exe

@@ -0,0 +1,18 @@
+
+#include <stdio.h>
+int main()
+{
+ float n;
+ scanf("%f", &n);
+ if (n <= 400.0)
+ printf("Novo salario: %.2fnReajuste ganho: %.2fnEm percentual: 15 %%n", n * 1.15, n * 0.15);
+ else if (n <= 800.0)
+ printf("Novo salario: %.2fnReajuste ganho: %.2fnEm percentual: 12 %%n", n * 1.12, n * 0.12);
+ else if (n <= 1200.0)
+ printf("Novo salario: %.2fnReajuste ganho: %.2fnEm percentual: 10 %%n", n * 1.10, n * 0.10);
+ else if (n <= 2000.0)
+ printf("Novo salario: %.2fnReajuste ganho: %.2fnEm percentual: 7 %%n", n * 1.07, n * 0.07);
+ else
+ printf("Novo salario: %.2fnReajuste ganho: %.2fnEm percentual: 4 %%n", n * 1.04, n * 0.04);
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/another.c

@@ -0,0 +1,17 @@
+// I used isdigit() function from ctype.h library so i tried to definition it.
+// I used isdigit() in p_1048.c
+
+#include <stdio.h>
+
+int main ()
+{
+ char a;
+ scanf("%c", &a);
+
+ if (a<48 || a>57)
+ {
+ printf("0");
+ }
+ else printf("1");
+ 
+}

Online platform problem solving/beecrowd/BEGINNER/isdigitfunction.c

@@ -0,0 +1,12 @@
+#include <stdio.h>
+#include <math.h>
+ 
+int main() {
+ 
+ double x1, y1, x2, y2, distance;
+ scanf("%lf%lf%lf%lf", &x1, &y1, &x2, &y2);
+ distance = sqrt(pow((x2-x1), 2) + pow((y2-y1), 2));
+ printf("%0.4lf", distance);
+ 
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/p_1015.c

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+#include <stdio.h>
+ 
+int main() {
+ 
+ int time, speed;
+ double fuel;
+ scanf("%d%d", &time, &speed);
+ fuel = (double)(time*speed)/12;
+ printf("%0.3lf\n", fuel);
+ 
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/p_1017.c

@@ -0,0 +1,79 @@
+#include <stdio.h>
+ 
+int main() {
+ 
+ int N;
+ scanf("%d", &N);
+ if (N>0 && N<1000000)
+ {
+ printf("%d\n", N);
+ if (N>=100)
+ {
+ printf("%d nota(s) de R$ 100,00\n", N/100);
+ N = N % 100;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 100,00\n");
+ }
+ if (N>=50)
+ {
+ printf("%d nota(s) de R$ 50,00\n", N/50);
+ N = N % 50;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 50,00\n");
+ }
+ if (N>=20)
+ {
+ printf("%d nota(s) de R$ 20,00\n", N/20);
+ N = N % 20;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 20,00\n");
+ }
+ if (N>=10)
+ {
+ printf("%d nota(s) de R$ 10,00\n", N/10);
+ N = N % 10;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 10,00\n");
+ }
+ if (N>=5)
+ {
+ printf("%d nota(s) de R$ 5,00\n", N/5);
+ N = N % 5;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 5,00\n");
+ }
+ if (N>=2)
+ {
+ printf("%d nota(s) de R$ 2,00\n", N/2);
+ N = N % 2;
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 2,00\n");
+ }
+ if (N>=1)
+ {
+ printf("%d nota(s) de R$ 1,00\n", N/1);
+ }
+ else
+ {
+ printf("0 nota(s) de R$ 1,00\n");
+ }
+ }
+ else
+ {
+ return 1;
+ }
+ 
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/p_1018.c

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+// Time Conversion
+#include <stdio.h>
+ 
+int main() {
+ 
+ int a, hrs, mins, secs;
+ scanf("%d", &a);
+ hrs = a/3600;
+ a = a % 3600;
+ mins = a/60;
+ a = a % 60;
+ secs = a;
+ printf("%d:%d:%d\n", hrs, mins, secs);
+ 
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/p_1019.c

@@ -0,0 +1,42 @@
+#include <stdio.h>
+ 
+int main() {
+ int n;
+ double N;
+ scanf("%lf", &N);
+ n = N;
+ int coin = (N-n)*100;//with coin we will be working with the floating values
+ if (N>=0 && N<=1000000)
+ {
+ printf("NOTAS:\n");
+ printf("%d nota(s) de R$ 100.00\n", n/100);
+ n = n%100;
+ printf("%d nota(s) de R$ 50.00\n", n/50);
+ n = n%50;
+ printf("%d nota(s) de R$ 20.00\n", n/20);
+ n = n%20;
+ printf("%d nota(s) de R$ 10.00\n", n/10);
+ n = n%10;
+ printf("%d nota(s) de R$ 5.00\n", n/5);
+ n = n%5;
+ printf("%d nota(s) de R$ 2.00\n", n/2);
+ n = n%2;
+ printf("MOEDAS:\n");
+ printf("%d moeda(s) de R$ 1.00\n", n/1);
+ printf("%d moeda(s) de R$ 0.50\n", coin/50);
+ coin = (coin%50);
+ printf("%d moeda(s) de R$ 0.25\n", coin/25);
+ coin = (coin%25);
+ printf("%d moeda(s) de R$ 0.10\n", coin/10);
+ coin = (coin%10);
+ printf("%d moeda(s) de R$ 0.05\n", coin/5);
+ coin = (coin%5);
+ printf("%d moeda(s) de R$ 0.01\n", coin/1);
+ }
+ else
+ {
+ return 1;
+ }
+ 
+ return 0;
+}

Online platform problem solving/beecrowd/BEGINNER/p_1021.c

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+#include <stdio.h>
+ 
+int main() {
+ 
+ int A, B, C, D;
+ scanf("%d%d%d%d", &A, &B, &C, &D);
+ if ((B>C && D>A) && (C+D > A+B))
+ {
+ if ((C>0 && D>0) && A%2==0)
+ {
+ printf("Valores aceitos\n");
+ }
+ else printf("Valores nao aceitos\n");
+ }
+ else printf("Valores nao aceitos\n");
+ 
+ return 0;
+}