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- 1$\begingroup$ But when you don't disconnect the oscillator portion, does Q2 ever turn off? If it does, it's AB/B/C, not A. The diagram indicates that the magnitude of the AC superimposed on the bias is greater than the bias itself, so C makes sense. $\endgroup$hobbs - KC2G– hobbs - KC2G2022-07-08 14:35:22 +00:00Commented Jul 8, 2022 at 14:35
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