Timeline for Only one answer allowed: which one to accept?
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:22 | history | edited | CommunityBot | replaced http://math.stackexchange.com/ with https://math.stackexchange.com/ | |
| May 20, 2014 at 15:31 | history | edited | user1729 | CC BY-SA 3.0 | added 4 characters in body |
| Dec 18, 2013 at 10:39 | answer | added | Lucian | timeline score: 6 | |
| Dec 18, 2013 at 2:02 | vote | accept | Gina | ||
| Dec 15, 2013 at 18:04 | comment | added | kettlecrab | @901301 sounds like a meta question to me. Of course that probably goes against your point... | |
| Dec 13, 2013 at 13:37 | comment | added | dreamer | Is it just me or is Meta overused recently? Try to think for yourselves people... (I'm not trying to offend anyone with this comment but really...) | |
| Dec 13, 2013 at 13:08 | answer | added | Marc van Leeuwen | timeline score: 5 | |
| Dec 10, 2013 at 19:54 | comment | added | achille hui | Just accept the one you like most. Note : "like", not useful nor even correct. It is your right to choose. If there are two answers you can't decide, flip a coin. If you are only a little bit uncomfortable with the outcome based on the coin, still follow the coin. If you are very uncomfortable, accept the other answer instead. | |
| Dec 10, 2013 at 10:11 | history | edited | Martin Sleziak | edited tags | |
| Dec 9, 2013 at 9:59 | comment | added | JRN | Just add a comment to your question, something to the effect of "I am grateful for all the answers as they have been very helpful to me. I have upvoted them all, but I can only select one. I've chosen [person]'s answer because ..." | |
| Dec 9, 2013 at 9:40 | comment | added | user642796 Mod | As you didn't post an answer to that question accepting your own answer isn't an option. But seriously, it really is up to you, and it is a decision you have to make. (Only be sure to upvote all answers that are helpful.) | |
| Dec 9, 2013 at 9:14 | comment | added | Asaf Karagila Mod | Roll a die, flip a coin, ask your favorite person to pick a number in a current range, rand() or variants of it, obtain U-238 isotopes and measure their radioactive decay apply SHA512 to the results - twice - and then sum the hexadecimal digits repeatedly until you have a single digit and use it modulo the number of answers you received. | |
| Dec 9, 2013 at 9:06 | comment | added | Gina | Thing is, I find them all useful, each in their own way. Most useful for submitting my homework would be my own answer, but that is probably not a good answer mathematically. If they all give the same solution, but one is more completed, then I can pick out the most useful one. But here they are equally useful, just different. | |
| Dec 9, 2013 at 8:59 | comment | added | user642796 Mod | Accept the one that you find most helpful, using whatever metric you use to judge this. It is your accept vote: hand it out as you wish. (I think I'm largely repeating Willie's answer from the other meta-thread.) | |
| Dec 9, 2013 at 8:55 | history | asked | Gina | CC BY-SA 3.0 |