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gave more-invariant search algorithm
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Let M0,M1,M2,M3,... be some canonical enumeration of Turing machines. ​ (Enumerations for
which the indices are polynomially related will yield the same answer to the question at the end
of this post.) ​ Let M be the Turing machine that takes a graph as input and works as follows:

Set i=1. ​ While none of the machines has outputted a Hamiltonian cycle in the graph:
For j in {0,1,2,3,...,i-1,i}, simulate Mj on the graph until it halts or has run for i steps.
(After the for loop, but still inside the while loop,) Increase i by 1.
When at least one of the machines has outputted a Hamiltonian cycle in the graph, halt.


Let T be the function from graphs to {0,1,2,3,...} given by
if M(G) halts then T(G) is the time M(G) runs for, else ​ T(G) = 0 .



With those definitions, the question could be interpreted as the following:


Are there functions f and g from {0,1,2,3,...} to (0,∞) such that
f is in nω(1) ​ and ​ g is in 2^(no(1)) ​ ​ ​ and ​ ​ ​ for all elements n of {0,1,2,3,...}, ​ f(n) < g(n)
and there is a zero-knowledge proof for the promise problem

Input: ​ a graph G with a Hamiltonian cycle
must output YES if: ​ g(size(G)) < T(G)
must output ​ NO if: ​ T(G) < f(size(G))

?

user57159