Timeline for What does $2^x$ really mean when $x$ is not an integer?
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| Apr 17, 2012 at 7:32 | comment | added | J. M. ain't a mathematician | Additionally, $2^{-p}$ can be interpreted as $(2^{-1})^p$, which leaves the problem of interpreting $2^{-1}$. If we want the exponent laws to hold, we should have $(2^1)(2^{-1})=2^0=1$, which rearranges to $2^{-1}=\frac1{2^1}$... | |
| Apr 16, 2012 at 22:11 | history | answered | Robert Israel | CC BY-SA 3.0 |