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Jul 26, 2015 at 15:22 vote accept aidandeno
Jul 26, 2015 at 15:22 vote accept aidandeno
Jul 26, 2015 at 15:22
Jul 26, 2015 at 15:17 comment added aidandeno @Dr.SonnhardGraubner: I might be wrong, but I think that the restriction on $n$ implies that we start at $n=1$
Jul 26, 2015 at 15:15 answer added wlad timeline score: 3
Jul 26, 2015 at 15:12 answer added N. S. timeline score: 2
Jul 26, 2015 at 15:11 comment added mercio it's not $2n$ and $2n+1$ but $2^n$ and $2^{n+1}$
Jul 26, 2015 at 15:11 comment added Dr. Sonnhard Graubner for what $n$ we are starting?
Jul 26, 2015 at 15:06 history asked aidandeno CC BY-SA 3.0