Timeline for Prove that $A+I$ is invertible if $A$ is nilpotent [duplicate]
Current License: CC BY-SA 3.0
26 events
| when toggle format | what | by | license | comment | |
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| Jan 14, 2020 at 17:04 | comment | added | Bill Dubuque | Special case of the method of simpler multiples, namely $$\color{#c00}{A^n = 0}\ \Rightarrow\ \dfrac{1}{A-c}\, =\, \dfrac{A^{n-1}+\cdots + c^{n-1}}{\color{#c00}{A^n}-c^n}\, =\, -c^{-n}(A^{n-1}+\cdots + c^{n-1})$$ | |
| Dec 29, 2019 at 10:43 | history | edited | Rodrigo de Azevedo | edited tags | |
| Jun 26, 2017 at 14:19 | history | edited | Sera Gunn | edited tags | |
| Apr 13, 2017 at 12:20 | history | edited | CommunityBot | replaced http://math.stackexchange.com/ with https://math.stackexchange.com/ | |
| Sep 10, 2013 at 12:59 | review | Reopen votes | |||
| Sep 10, 2013 at 14:16 | |||||
| Sep 9, 2013 at 12:58 | review | Reopen votes | |||
| Sep 9, 2013 at 14:23 | |||||
| Jul 25, 2013 at 21:44 | history | edited | user26857 | CC BY-SA 3.0 | deleted 54 characters in body |
| May 4, 2012 at 10:37 | comment | added | t.b. | Please don't do this. There's nothing wrong with a closed question while an impenetrable non-question has no value whatsoever. | |
| May 4, 2012 at 10:35 | history | rollback | Rudy the Reindeer | Rollback to Revision 7 | |
| May 4, 2012 at 10:34 | history | edited | ugoolm | CC BY-SA 3.0 | deleted 182 characters in body |
| May 4, 2012 at 10:33 | history | rollback | t.b. | Rollback to Revision 5 | |
| May 4, 2012 at 10:31 | history | edited | ugoolm | CC BY-SA 3.0 | deleted 186 characters in body |
| May 4, 2012 at 9:58 | history | edited | CommunityBot | insert duplicate link | |
| May 4, 2012 at 9:58 | history | closed | Bill Dubuque CommunityBot Bruno Joyal AD - Stop Putin - t.b. | exact duplicate | |
| May 3, 2012 at 21:51 | comment | added | AD - Stop Putin - | I think it would be sufficient with a hint like "Do you remember the proof of the geometric formula?". | |
| May 3, 2012 at 21:13 | answer | added | Manos | timeline score: 4 | |
| May 3, 2012 at 14:44 | comment | added | user38268 | @ugoolm If you are asking for help with your MATH 1115 assignment due this monday, you should provide a bit more context and where you are stuck. | |
| May 3, 2012 at 14:43 | history | edited | Bill Dubuque | CC BY-SA 3.0 | edited title |
| May 3, 2012 at 14:12 | answer | added | Arturo Magidin | timeline score: 21 | |
| May 3, 2012 at 13:36 | comment | added | mike | On the other hand, if I + A not invertible there is a v so that $0 = (I + A) v$, so $Av = -v, A^{2012}v = v, $ A not nilpotent. | |
| May 3, 2012 at 11:31 | answer | added | Nathaniel Bubis | timeline score: 44 | |
| May 3, 2012 at 11:30 | history | edited | Davide Giraudo | CC BY-SA 3.0 | added 1 characters in body; edited tags; edited title |
| May 3, 2012 at 11:29 | answer | added | Davide Giraudo | timeline score: 5 | |
| S May 3, 2012 at 11:28 | history | suggested | Siminore | CC BY-SA 3.0 | Inserted TeX syntax |
| May 3, 2012 at 11:24 | review | Suggested edits | |||
| S May 3, 2012 at 11:28 | |||||
| May 3, 2012 at 11:22 | history | asked | ugoolm | CC BY-SA 3.0 |