Timeline for The product of two spectral spaces
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 30, 2012 at 10:13 | vote | accept | wxu | ||
| May 30, 2012 at 10:11 | comment | added | wxu | I agree with you. Also, even if $A=B$ are DVRs, the ring $C$ will become a non-Noetherian ring (by krull's principal theorem). | |
| May 30, 2012 at 9:37 | comment | added | user18119 | @wxu, thanks. For your second question, I don't think there is a reasonnable answer. For example, if $Y$ is the spectrum of a field $K$, so $X\times Y= X$, then what would be $C$ ? Remember that you can't recover the ring $A$ from $X$. | |
| May 30, 2012 at 0:47 | comment | added | wxu | Dear @QiL, Your proof is very very clear! Beautiful writting. Thanks! | |
| May 29, 2012 at 20:52 | history | undeleted | CommunityBot | ||
| May 29, 2012 at 20:52 | history | edited | user18119 | CC BY-SA 3.0 | added 178 characters in body |
| May 29, 2012 at 14:57 | history | deleted | CommunityBot | ||
| May 29, 2012 at 14:55 | history | edited | user18119 | CC BY-SA 3.0 | added 110 characters in body |
| May 29, 2012 at 14:01 | history | answered | user18119 | CC BY-SA 3.0 |