Timeline for Proving $\mathbb{Z}[i] / (7+5i) \cong \mathbb{Z}_{74}$.
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 24, 2018 at 17:10 | review | Close votes | |||
| Nov 29, 2018 at 3:05 | |||||
| Nov 24, 2018 at 16:50 | comment | added | Watson | Possible duplicate of Quotient ring of Gaussian integers | |
| Jun 11, 2012 at 18:50 | answer | added | Cameron Buie | timeline score: 6 | |
| Jun 11, 2012 at 17:59 | comment | added | Matt E | Dear user, A very similar question was asked and answered here: math.stackexchange.com/q/23358/221 See this answer in particular. Regards, | |
| Jun 11, 2012 at 17:56 | comment | added | Andrea | $\phi$ is surjective because $31$ is a square root of $-1$ modulo $74$, hence $\phi(31) \in i + \langle 74 \rangle \subseteq i + \langle 7 + 5i \rangle$. | |
| Jun 11, 2012 at 17:53 | answer | added | Bill Dubuque | timeline score: 7 | |
| Jun 11, 2012 at 17:52 | comment | added | user26069 | Ah yes I do, I've edited that in | |
| Jun 11, 2012 at 17:51 | history | edited | user26069 | CC BY-SA 3.0 | added 46 characters in body |
| Jun 11, 2012 at 17:51 | comment | added | Dylan Moreland | Can you prove that $74$ is at least contained in the kernel? Do you know that this map is surjective? | |
| Jun 11, 2012 at 17:43 | comment | added | Belgi | you probably mean $\langle 74 \rangle$ | |
| Jun 11, 2012 at 17:42 | history | asked | user26069 | CC BY-SA 3.0 |