Timeline for How to explain what it means to say a function is "defined" on an interval?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 5, 2012 at 18:40 | answer | added | Spencer | timeline score: 3 | |
| Jul 5, 2012 at 17:36 | history | edited | MJD | CC BY-SA 3.0 | retitle |
| Jul 5, 2012 at 17:35 | vote | accept | Sandra | ||
| Jul 5, 2012 at 17:31 | comment | added | Sandra | Great. Thanks Matt, J.D., J.M. and Pritam. Now I got an idea on how to explain it. | |
| Jul 5, 2012 at 17:28 | comment | added | pritam | "$f$ is defined on the closed interval $[a,b]$" means the 'domain' of $f$ is $[a,b]$ (Note that 'domain','codomain' are necessary ingredients to describe any function). | |
| Jul 5, 2012 at 17:28 | answer | added | user29743 | timeline score: 10 | |
| Jul 5, 2012 at 17:27 | comment | added | J. M. ain't a mathematician | ...or, put another way, the function has no discontinuities within the closed interval being considered. | |
| Jul 5, 2012 at 17:26 | comment | added | user2468 | $f$ is defined on the interval $[a, b],$ means that we know $f$ (either its value, its expression, or how to compute it) for every $x \in [a, b].$ Outside this interval, we know nothing about $f.$ | |
| Jul 5, 2012 at 17:20 | history | asked | Sandra | CC BY-SA 3.0 |