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Jun 15, 2016 at 1:44 answer added N. F. Taussig timeline score: 0
Jun 15, 2016 at 0:16 answer added awkward timeline score: 0
Jun 15, 2016 at 0:14 comment added hardmath Sadly it does not "end up being 26C8 divided by... something". You are counting how many color combinations are possible (outcomes distinguishable only by the number of each color). While the possible colors will add up to $8$ in each outcome, and the colors give an "order" to those summands, it is not as simple as how many weak compositions of $8$ there are with at most $8$ summands (the number of colors), because you have bounds on how large certain summands can be (only the count of red balls can be as large as all $8$).
Jun 14, 2016 at 22:23 review Close votes
Jun 15, 2016 at 1:05
Jun 14, 2016 at 22:12 answer added user326210 timeline score: 1
Jun 14, 2016 at 22:01 history edited jedi.jesse CC BY-SA 3.0
added 58 characters in body
Jun 14, 2016 at 21:55 review First posts
Jun 14, 2016 at 22:01
Jun 14, 2016 at 21:52 history asked jedi.jesse CC BY-SA 3.0