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S Sep 25, 2016 at 0:51 history bounty ended CommunityBot
S Sep 25, 2016 at 0:51 history notice removed user141854
Sep 25, 2016 at 0:51 answer added Jose Arnaldo Bebita Dris timeline score: 1
Sep 24, 2016 at 3:07 vote accept CommunityBot
Sep 24, 2016 at 1:02 answer added Alexis Olson timeline score: 1
Sep 24, 2016 at 0:37 comment added user141854 Indeed it is more intuitive to think of squares that way. This is why the number of divisors function above returns an odd value for perfect squares.
Sep 23, 2016 at 23:51 comment added Alexis Olson Your statement about the number of divisors of $Q$ is equivalent to saying all the primes $p_i$ in $Q$'s decomposition are have even powers (which is a more intuitive way of thinking about square numbers, IMO).
Sep 23, 2016 at 20:54 history tweeted twitter.com/StackMath/status/779423686940094464
S Sep 23, 2016 at 20:26 history bounty started CommunityBot
S Sep 23, 2016 at 20:26 history notice added user141854 Draw attention
Sep 23, 2016 at 20:24 history edited user141854 CC BY-SA 3.0
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Sep 22, 2016 at 20:31 history edited user141854 CC BY-SA 3.0
Clarified my new question
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