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Mar 9, 2017 at 10:01 vote accept Sebastian TG
Mar 9, 2017 at 6:58 answer added Claude Leibovici timeline score: 1
Mar 8, 2017 at 19:37 vote accept Sebastian TG
Mar 9, 2017 at 10:01
Mar 8, 2017 at 19:32 comment added Jean Marie @Dr. Sonnhard Graubner You should check twice what you write before writing it : this solution is erroneous.
Mar 8, 2017 at 19:30 comment added BobaFret It's not a Cauchy-Euler equation. $2x^2 y'' +4x y' - y = 0$ is one though.
Mar 8, 2017 at 19:29 answer added Hrhm timeline score: 1
Mar 8, 2017 at 19:22 answer added mrnovice timeline score: 0
Mar 8, 2017 at 19:15 answer added shdp timeline score: 0
Mar 8, 2017 at 19:13 history edited gymbvghjkgkjkhgfkl CC BY-SA 3.0
edited body
Mar 8, 2017 at 19:12 comment added Dr. Sonnhard Graubner hint: $$y=-\frac{1}{x}$$ is one solution
Mar 8, 2017 at 19:05 comment added mrnovice Try the substitution: $x=e^{z}$
Mar 8, 2017 at 19:05 comment added Chee Han This is a Cauchy-Euler equation. See en.wikipedia.org/wiki/Cauchy%E2%80%93Euler_equation
Mar 8, 2017 at 19:04 history asked Sebastian TG CC BY-SA 3.0