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Mar 22, 2017 at 19:39 history edited Santana Afton CC BY-SA 3.0
clarification of a mistake I made
Mar 21, 2017 at 15:01 comment added CiaPan There is no largest element in a described order, unless $S$ is empty (in which case the empty function is the only candidate) or $T$ is a singleton (in which case the largest element is a function whose domain is whole $S$).
Mar 21, 2017 at 13:02 comment added Zed Yeah, but that's not the only condition, like if we take all functions greater than f and g the least upper bound is the function that is relates to both f and g but it's immediately above it (if we looked at the hassle diagram of the relation)
Mar 21, 2017 at 12:58 comment added Santana Afton By greatest lower bound, do you mean the greatest function which is less than both $f$ and $g$?
Mar 21, 2017 at 12:53 comment added Zed For the example you wrote it is the case iff your function was 1/x, otherwise the greatest element is the element that maps the whole source set, right? Also the greatest lower bound of f and g will be defined by the intersection of Dom(f) and Dom(g), and for the least upper bound it will be defined by their union of the domains, does that sound right? Thanks.
Mar 21, 2017 at 12:37 comment added Santana Afton That's a good point that I overlooked, thank you! I edited my response to reflect the change.
Mar 21, 2017 at 12:36 history edited Santana Afton CC BY-SA 3.0
Fixed error in argument.
Mar 21, 2017 at 12:06 comment added Zed I understood the relation now thanks, the minimal and maximal elements are also the least and the greatest since they are the only minimal and maximal, right? Thanks
Mar 21, 2017 at 10:47 history answered Santana Afton CC BY-SA 3.0