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Explore Stack InternalI need a bit of help with intergratingintegrating factors in differential equations in the following question. Bit confused how to rearrange to get the correct format needed: $$(1+x^2)\frac{dy}{dx}-\frac{4x^3y}{1-x^2} = 1$$
$\text{Use the integrating factor method to find the general solution and show that:}$ Use the integrating factor method to find the general solution and show that: $$y=\frac{k+3x-x^3}{3(1-x^4)}$$
Thanks in advance.
I need a bit of help with intergrating factors in differential equations in the following question. Bit confused how to rearrange to get the correct format needed: $$(1+x^2)\frac{dy}{dx}-\frac{4x^3y}{1-x^2} = 1$$
$\text{Use the integrating factor method to find the general solution and show that:}$ $$y=\frac{k+3x-x^3}{3(1-x^4)}$$
Thanks in advance.
I need a bit of help with integrating factors in differential equations in the following question. Bit confused how to rearrange to get the correct format needed: $$(1+x^2)\frac{dy}{dx}-\frac{4x^3y}{1-x^2} = 1$$
Use the integrating factor method to find the general solution and show that: $$y=\frac{k+3x-x^3}{3(1-x^4)}$$
Thanks in advance.
I need a bit of help with intergrating factors in differential equations in the following question. Bit confused how to rearrange to get the correct format needed: $$(1+x^2)\frac{dy}{dx}-\frac{4x^3y}{1-x^2} = 1$$
$\text{Use the integrating factor method to find the general solution and show that:}$ $$y=\frac{k+3x-x^3}{3(1-x^4)}$$
Thanks in advance.
