Timeline for integration by partial fraction
Current License: CC BY-SA 2.5
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 10, 2011 at 2:55 | comment | added | Arturo Magidin | @user8051: After you find that $A=4$, plug it in and simplify, like I did in my answer above. | |
| Mar 10, 2011 at 2:36 | comment | added | Brian | If two functions are equal, they have to be equal for any x, so you can choose any three values of x to plug in to find A,B, and C. It just happens that choosing values that will cancel out some of the terms (if there are any) are the easiest ones to choose. If there aren't enough like this you can choose any other "easy" values. Eric's method will always work too. | |
| Mar 10, 2011 at 2:04 | comment | added | user8051 | Yeah i see how you got that. My professor just taught us to plug in numbers for x and solve for the variables. i.e x=0 then A=4 because B and C cancel, which is also what you got above. but i couldnt find anything to cancel the A because of the x^2. Thank you for all your help | |
| Mar 10, 2011 at 1:56 | history | answered | Eric Naslund | CC BY-SA 2.5 |