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DonAntonio
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How to prove that $\int_$\int\limits_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$?

I am stuck trying to show that $\displaystyle \int_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$$\displaystyle \int\limits_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$

I have tried using a Squeeze Theorem type approach, but at $\pi/4$ any function I choose overlaps and becomes less than or greater than the function depending. I am not sure where to start anymore. Anything will be helpful. Thank you in advance!

How to prove that $\int_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$?

I am stuck trying to show that $\displaystyle \int_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$

I have tried using a Squeeze Theorem type approach, but at $\pi/4$ any function I choose overlaps and becomes less than or greater than the function depending. I am not sure where to start anymore. Anything will be helpful. Thank you in advance!

How to prove that $\int\limits_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$?

I am stuck trying to show that $\displaystyle \int\limits_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$

I have tried using a Squeeze Theorem type approach, but at $\pi/4$ any function I choose overlaps and becomes less than or greater than the function depending. I am not sure where to start anymore. Anything will be helpful. Thank you in advance!

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Yousuf Soliman
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How to prove that $\int_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$?

I am stuck trying to show that $\displaystyle \int_{-\pi/2}^{\pi/2}\frac{\cos(2x)}{e^x+1}=0$

I have tried using a Squeeze Theorem type approach, but at $\pi/4$ any function I choose overlaps and becomes less than or greater than the function depending. I am not sure where to start anymore. Anything will be helpful. Thank you in advance!