Return to Question

suppose we have an isosceles trapezoid whose length of the associated square is 20 and the length of the hypotenuse of the triangles is 30. I want to determine if it is possible to find the height of the triangles, I think no.

http://mathworld.wolfram.com/IsoscelesTrapezoid.html

So in our case a=20 and c=30, we want to find h.

Suppose x is the base of one of the triangles, note that x can be free. Then x^2+h^2=30^2 so simply pick two distinct such x and then h will not be unique.

Is this correct?

Suppose we have an isosceles trapezoid whose length of the associated square is $20$ and the length of the hypotenuse of the triangles is $30$. I want to determine if it is possible to find the height of the triangles, I think no.

(Taken from http://mathworld.wolfram.com/IsoscelesTrapezoid.html.)

So in our case $a = 20$ and $c = 30$, we want to find $h$.

Suppose $x$ is the base of one of the triangles, note that $x$ can be free. Then $x^2 + h^2 = 30^2$ so simply pick two distinct such $x$ and then $h$ will not be unique.

Is this correct?

suppose we have an isosceles triangle whose length of the associated square is 20 and the length of the hypotenuse of the triangles is 30. I want to determine if it is possible to find the height of the triangles, I think no.

http://mathworld.wolfram.com/IsoscelesTrapezoid.html

So in our case a=20 and c=30, we want to find h.

Suppose x is the base of one of the triangles, note that x can be free. Then x^2+h^2=30^2 so simply pick two distinct such x and then h will not be unique.

Is this correct?

suppose we have an isosceles trapezoid whose length of the associated square is 20 and the length of the hypotenuse of the triangles is 30. I want to determine if it is possible to find the height of the triangles, I think no.

http://mathworld.wolfram.com/IsoscelesTrapezoid.html

So in our case a=20 and c=30, we want to find h.

Suppose x is the base of one of the triangles, note that x can be free. Then x^2+h^2=30^2 so simply pick two distinct such x and then h will not be unique.

Is this correct?

suppose we have an isosceles triangle whose length of the associated square is 20 and the length of the hypotenuse of the triangles is 30. I want to determine if it is possible to find the height of the triangles, I think no.

Suppose x is the base of one of the triangles, note that x can be free. Then x^2+h^2=30^2 so simply pick two distinct such x and then h will not be unique.

Is this correct?

suppose we have an isosceles triangle whose length of the associated square is 20 and the length of the hypotenuse of the triangles is 30. I want to determine if it is possible to find the height of the triangles, I think no.

http://mathworld.wolfram.com/IsoscelesTrapezoid.html

So in our case a=20 and c=30, we want to find h.

Suppose x is the base of one of the triangles, note that x can be free. Then x^2+h^2=30^2 so simply pick two distinct such x and then h will not be unique.

Is this correct?