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You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can decide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid. And now you just combine that with Godel's completeness result: if $\varphi$ is valid, then it is provable, and if $\varphi$ is not valid, then it is not provable.

So for that first part: if you have algorithm $\mathcal{A}$ that can figure put whether $\varphi$ is satisfiable or not for any $\varphi$, then design algorithm $\mathcal{B}$ that is trying to figure out whether $\varphi$ is provable or not as follows:

1. Take in $\varphi$

2. Negate $\varphi$

3. Call algorithm $\mathcal{A}$ with $\neg \varphi$

4a. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is satisfiable, then print '$\varphi$ is not provable!'

4b. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is not satisfiable, then print '$\varphi$ is provable!'

You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can decide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid. And now you just combine that with Godel's completeness result (to be precise: the theorem that a statement is provable if and only if it is valid ... the more difficult 'if' part of which is the completeness theorem): if $\varphi$ is valid, then it is provable, and if $\varphi$ is not valid, then it is not provable.

So for that first part: if you have algorithm $\mathcal{A}$ that can figure put whether $\varphi$ is satisfiable or not for any $\varphi$, then design algorithm $\mathcal{B}$ that is trying to figure out whether $\varphi$ is provable or not as follows:

1. Take in $\varphi$

2. Negate $\varphi$

3. Call algorithm $\mathcal{A}$ with $\neg \varphi$

4a. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is satisfiable, then print '$\varphi$ is not provable!'

4b. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is not satisfiable, then print '$\varphi$ is provable!'

You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can decide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid. And now you just combine that with Godel's completeness result: if $\varphi$ is valid, then it is provable, and if $\varphi$ is not valid, then it is not provable.

You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can decide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid. And now you just combine that with Godel's completeness result: if $\varphi$ is valid, then it is provable, and if $\varphi$ is not valid, then it is not provable.

So for that first part: if you have algorithm $\mathcal{A}$ that can figure put whether $\varphi$ is satisfiable or not for any $\varphi$, then design algorithm $\mathcal{B}$ that is trying to figure out whether $\varphi$ is provable or not as follows:

1. Take in $\varphi$

2. Negate $\varphi$

3. Call algorithm $\mathcal{A}$ with $\neg \varphi$

4a. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is satisfiable, then print '$\varphi$ is not provable!'

4b. If algorithm $\mathcal{A}$ says that $\neg \varphi$ is not satisfiable, then print '$\varphi$ is provable!'

You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can cide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid.

You got the right idea for part 1, but it is unusual to use the logical notation that you do: $\neg$, $\forall$, and $\exists$ are logical operators, but $\models$ is a metalogic symbol; purists will not like you mixing those up. So, it may be better to use the English 'some' and 'all' and 'not'

For part 2: here is where you use the result of part 1! In particular, in order to decide whether $\varphi$ is valid or not, you can decide whether $\neg \varphi$ is satisfiable or not: if $\neg \varphi$ is satisfiable, then $\varphi$ is not valid, but if $\neg \varphi$ is not satisfiable, then $\varphi$ is valid. And now you just combine that with Godel's completeness result: if $\varphi$ is valid, then it is provable, and if $\varphi$ is not valid, then it is not provable.