Let us consider two planes with equations:
P1 : x + 2y + 3z = 3$P_1 : x + 2y + 3z = 3$ and P2 : 2x-y = 5$P_2 : 2x-y = 5$
By substituting x$x$ as 0$0$, can I say that the point (0,-5,13/3)$(0,-5,13/3)$ lies on the line of intersection of two planes?
And if if I find that the direction vector of the line of intersection is (3,5,-5)$(3,5,-5)$, Can iI say that the equation of the line of intersection of two planes is (0,-5,13/3) + t(3,5,-5)$(0,-5,13/3) + t(3,5,-5)$ ?