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May 30, 2019 at 7:36 history edited José Carlos Santos CC BY-SA 4.0
Fixing typo
May 30, 2019 at 7:05 history edited Rodrigo de Azevedo
edited tags
Apr 24, 2019 at 4:37 comment added YiFan Tey @HenningMakholm that's a very good point. But before the responses to the question, it's the only method I knew (hence all my approaches were based on that).
Apr 24, 2019 at 0:23 comment added hmakholm left over Monica All eigenvalues distinct is a sufficient but not necessary condition for a matrix to be diagonalizable.
Apr 23, 2019 at 23:10 history became hot network question
Apr 23, 2019 at 23:05 vote accept CommunityBot moved from User.Id=496634 by developer User.Id=1054405
Apr 23, 2019 at 22:57 answer added gcousin timeline score: 8
Apr 23, 2019 at 22:56 answer added José Carlos Santos timeline score: 36
Apr 23, 2019 at 22:52 answer added JimmyK4542 timeline score: 31
Apr 23, 2019 at 22:43 history asked YiFan Tey CC BY-SA 4.0