Timeline for Can we express median in terms of standard operations?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 6, 2020 at 23:14 | answer | added | Mike Earnest | timeline score: 1 | |
| Feb 6, 2020 at 7:25 | comment | added | Lee David Chung Lin | How about the answer by @GEdgar in this old post? | |
| Feb 5, 2020 at 17:41 | comment | added | StubbornAtom | If $a_{(1)}\le a_{(2)}\le \cdots\le a_{(n)}$ are the ordered observations, then median of $(a_1,a_2,\ldots,a_n)$ for odd $n$ is $a_{\left(\frac{n+1}{2}\right)}$. | |
| Feb 5, 2020 at 12:50 | answer | added | Yannik | timeline score: 0 | |
| Feb 5, 2020 at 9:48 | answer | added | aryan bansal | timeline score: -1 | |
| Feb 5, 2020 at 9:42 | comment | added | pH 74 | @Idnoknow see this answer | |
| Feb 5, 2020 at 9:25 | comment | added | Idonknow | @PeterSheldrick May I have a proof of the formula or reference that you provide above? | |
| Feb 5, 2020 at 9:17 | comment | added | user11260 | For the median pick one of the $a_1,a_2,...$ to find the minimum of the sums $|a_1-a_1|+|a_2-a_1|+|a_3-a_1|...$ and $|a_1-a_2|+|a_2-a_2|+|a_3-a_2|...$ and so on | |
| Feb 5, 2020 at 9:12 | history | edited | Idonknow | CC BY-SA 4.0 | edited title |
| Feb 5, 2020 at 9:03 | history | asked | Idonknow | CC BY-SA 4.0 |