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Jun 15, 2021 at 7:40 answer added Ujjwal timeline score: 1
Jul 14, 2020 at 1:46 vote accept Mathsisfun
Jul 13, 2020 at 17:42 answer added Dominik Kutek timeline score: 1
Jul 13, 2020 at 16:46 answer added Luis Sierra timeline score: 8
Jul 13, 2020 at 16:30 comment added Eeyore Ho $ I=\Re \int_{-\infty}^{\infty}\frac{e^{2ix}}{x^2+4} \,dx $
Jul 13, 2020 at 14:48 comment added Mathsisfun @Mark I'm not so familiar with it but I'll have a look at it and learn more about it.
Jul 13, 2020 at 14:46 comment added Mark The easiest way is using the residue theorem from complex analysis. Are you familiar with it? The answer is indeed $\frac{\pi}{2e^4}$.
Jul 13, 2020 at 14:45 history edited Mathsisfun CC BY-SA 4.0
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Jul 13, 2020 at 14:45 comment added Jared This is a stab in the dark but my guess is that this is a Cauchy Theorem problem (complex analysis).
Jul 13, 2020 at 14:42 history asked Mathsisfun CC BY-SA 4.0