Timeline for Understanding when to use residue theorem and when Cauchy's formula to solve integrals
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 30, 2020 at 20:32 | vote | accept | Toma | ||
| Jul 30, 2020 at 20:32 | comment | added | Toma | Oh you're right I forgot that the middle is not $-3 \pi$ but $3 \pi $ haha | |
| Jul 30, 2020 at 16:29 | comment | added | Klaus | No, none of these are removable. By the way, the relevant poles should be $2\pi$, $3\pi$ and $4\pi$ and the corresponding residues are $\frac{1}{2\pi}$, $-\frac{1}{3\pi}$ and $\frac{1}{4\pi}$. Not sure how you got $0$. | |
| Jul 30, 2020 at 16:21 | comment | added | Toma | Is a removable singularity the reason for the 0? which one is the removable? | |
| Jul 30, 2020 at 16:07 | history | answered | Klaus | CC BY-SA 4.0 |