Timeline for Relationship determinant symmetric matrix and skew-symmetric counterpart
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 9, 2020 at 13:48 | history | edited | user1551 | CC BY-SA 4.0 | added 35 characters in body |
| Nov 9, 2020 at 13:42 | vote | accept | mfnx | ||
| Nov 9, 2020 at 13:39 | comment | added | user1551 | @mfnx That is correct. $\det(A)$ is not a function of $\det(B)$ and $\det(C)$. | |
| Nov 9, 2020 at 13:38 | history | edited | user1551 | CC BY-SA 4.0 | added 302 characters in body |
| Nov 9, 2020 at 13:28 | comment | added | mfnx | From what you say, is it correct to deduce that, even for odd n, there is no function f such that det(A) = f(det(B))? | |
| Nov 9, 2020 at 13:01 | history | answered | user1551 | CC BY-SA 4.0 |