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mathlove
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Let $X(a,b),O(0,0),A(1,0),B(3,4)$.

Then, as you pointed out, we want to minimize $XO+XA+XA+XB$.

  • $XO+XA\geqslant OA=1$ For any $X$, it holds that $XO+XA\geqslant OA$ whose equality is attained when $X$ is on the line segment $OA$.

  • $XA+XB\geqslant AB=2\sqrt 5$ For any $X$, it holds that $XA+XB\geqslant AB$ whose equality is attained when $X$ is on the line segment $AB$.

Therefore, for any $X$, it followsholds that $$XO+XA+XA+XB\geqslant 1+2\sqrt 5$$$$XO+XA+XA+XB\geqslant OA+AB=1+2\sqrt 5$$ whose equality is attained when $X=A$.

Let $X(a,b),O(0,0),A(1,0),B(3,4)$.

Then, as you pointed out, we want to minimize $XO+XA+XA+XB$.

  • $XO+XA\geqslant OA=1$ whose equality is attained when $X$ is on the line segment $OA$.

  • $XA+XB\geqslant AB=2\sqrt 5$ whose equality is attained when $X$ is on the line segment $AB$.

Therefore, it follows that $$XO+XA+XA+XB\geqslant 1+2\sqrt 5$$ whose equality is attained when $X=A$.

Let $X(a,b),O(0,0),A(1,0),B(3,4)$.

Then, as you pointed out, we want to minimize $XO+XA+XA+XB$.

  • For any $X$, it holds that $XO+XA\geqslant OA$ whose equality is attained when $X$ is on the line segment $OA$.

  • For any $X$, it holds that $XA+XB\geqslant AB$ whose equality is attained when $X$ is on the line segment $AB$.

Therefore, for any $X$, it holds that $$XO+XA+XA+XB\geqslant OA+AB=1+2\sqrt 5$$ whose equality is attained when $X=A$.

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mathlove
  • 155.1k
  • 10
  • 127
  • 315

Let $X(a,b),O(0,0),A(1,0),B(3,4)$.

Then, as you pointed out, we want to minimize $XO+XA+XA+XB$.

  • $XO+XA\geqslant OA=1$ whose equality is attained when $X$ is on the line segment $OA$.

  • $XA+XB\geqslant AB=2\sqrt 5$ whose equality is attained when $X$ is on the line segment $AB$.

Therefore, it follows that $$XO+XA+XA+XB\geqslant 1+2\sqrt 5$$ whose equality is attained when $X=A$.