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Jan 2, 2022 at 9:15 history edited Johnnuy junk CC BY-SA 4.0
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Jan 2, 2022 at 8:59 vote accept Johnnuy junk
Jan 1, 2022 at 12:54 history edited Jose Avilez CC BY-SA 4.0
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Jan 1, 2022 at 10:11 answer added callculus42 timeline score: 2
Jan 1, 2022 at 5:57 history edited RobPratt CC BY-SA 4.0
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Jan 1, 2022 at 5:46 history edited RobPratt CC BY-SA 4.0
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Jan 1, 2022 at 5:18 comment added Johnnuy junk Thanks i edited the question
Jan 1, 2022 at 5:18 history edited Johnnuy junk CC BY-SA 4.0
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Jan 1, 2022 at 3:30 comment added RobPratt Setting $t_1=0$ yields $7y_1+2y_2=2$.
Jan 1, 2022 at 0:56 comment added Brian Borchers Note that you should check that $x=(2,0,0)$ is primal feasible. $y$ must also satisfy the dual constraints. If you can find any vector $y$ with $7y_{1}-3y_{2}=0$ that also satisfies the other dual constraints then you will have shown that $x=(2,0,0)$ is optimal. There's no reason to expect the optimal dual solution $y$ to be unique.
Jan 1, 2022 at 0:16 history edited Johnnuy junk CC BY-SA 4.0
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Jan 1, 2022 at 0:10 history asked Johnnuy junk CC BY-SA 4.0