Timeline for How can I compute the integral $\int_{0}^{\infty} \frac{dt}{1+t^4}$?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:21 | history | edited | CommunityBot | replaced http://math.stackexchange.com/ with https://math.stackexchange.com/ | |
| Nov 15, 2011 at 6:54 | comment | added | André Nicolas | Indeed it is nicer, symmetrizes in one swoop. | |
| Nov 15, 2011 at 6:45 | comment | added | Ragib Zaman | A nicer miracle: $ \displaystyle \int^1_0 \frac{1+t^2}{1+t^4} dt = \int^1_0 \frac{d(t-1/t) }{(t-1/t)^2+2} = \frac{1}{\sqrt{2}} \arctan \left( \frac{t-1/t}{\sqrt{2}} \right) \Bigg|^1_0 = \frac{\pi}{2\sqrt{2} }$ | |
| Jun 5, 2011 at 21:21 | history | edited | André Nicolas | CC BY-SA 3.0 | added 479 characters in body |
| Jun 5, 2011 at 19:53 | history | answered | André Nicolas | CC BY-SA 3.0 |