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May 30, 2022 at 11:57 comment added Matthé van der Lee This trivially holds if $R$ is semi-local (finitely many maximal ideals). And for Dedekind domains (assuming $\text{ann}_R(x) \ne 0$, of course). These are one-dimensional.
May 30, 2022 at 10:37 comment added Aleksei Kubanov I'm curious about a condition that $\mathrm{ann}_R(x)$ is contained in only finitely many max. ideals. Are there any cases when this condition is satisfied automatically? What about one-dimesional domains in particular?
May 30, 2022 at 10:30 vote accept Aleksei Kubanov
May 30, 2022 at 10:28 comment added Aleksei Kubanov Thank you! I guess, in case $\mathfrak{p}$ is maximal, we could argue that the ring $R / \mathfrak{p}^\alpha$ is local with max. ideal $\mathfrak{p} / \mathfrak{p}^\alpha$, thus it satisfies the UMP of localization, 'cause its invertible elements are precisely the ones not in $\mathfrak{p}$. Is that right? So I believe it makes sense to pose my question in context of one-dimesional domains, yes?
May 29, 2022 at 18:37 history edited Matthé van der Lee CC BY-SA 4.0
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May 29, 2022 at 18:31 history answered Matthé van der Lee CC BY-SA 4.0