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Nov 6, 2023 at 17:15 vote accept Daniel
Nov 5, 2023 at 11:45 answer added José Carlos Santos timeline score: 2
Nov 5, 2023 at 11:44 comment added Mengchun Zhang We have $a_n> s-\varepsilon$, so $-a_n<\varepsilon-s$, along with $a_m\leq s$, it follows $a_m-a_n<s+(\varepsilon-s)=\varepsilon$
Nov 5, 2023 at 11:40 history asked Daniel CC BY-SA 4.0