Timeline for Function is uniformly convergent on interval?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Apr 26, 2024 at 20:41 | comment | added | Maxxer | Uniform convergence on an interval means that this sequence is uniformly convergent on (a, b) because it can be non-uniformly convergent or even divergent outside of this interval. Because the domain is an (a, b) interval think of it as normal uniform convergence. Just remember to put $x∈(a,b)$ everywhere needed in your proof. | |
| Apr 26, 2024 at 20:27 | history | edited | Jose Avilez | CC BY-SA 4.0 | deleted 7 characters in body |
| S Apr 26, 2024 at 20:11 | vote | accept | rudinable | ||
| S Apr 26, 2024 at 20:11 | vote | accept | rudinable | ||
| S Apr 26, 2024 at 20:11 | |||||
| Apr 26, 2024 at 20:11 | vote | accept | rudinable | ||
| S Apr 26, 2024 at 20:11 | |||||
| Apr 26, 2024 at 18:36 | comment | added | GEdgar | It is not the function $f$ that is uniformly convergent. The series $\sum_{n=1}^\infty f_n$ is uniformly convergent. It is perhaps confusing (but nevertheless common) to use the same letter for the series and for the sum of the series. | |
| Apr 26, 2024 at 18:34 | answer | added | Mousedorff | timeline score: 1 | |
| Apr 26, 2024 at 18:27 | answer | added | Jose Avilez | timeline score: 1 | |
| Apr 26, 2024 at 18:27 | comment | added | Mason | $g$ is uniformly convergence means the partial sums are uniformly convergent (to $g$). | |
| Apr 26, 2024 at 18:24 | history | asked | rudinable | CC BY-SA 4.0 |