Timeline for How to recover the vector $x$ when multiplying it with a matrix $A$ that has a specific structure
Current License: CC BY-SA 4.0
13 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 6, 2024 at 16:26 | comment | added | Sajjad | Could you please add the details to the answer? What will be the vector $x$ in that case ? | |
| Sep 6, 2024 at 15:54 | comment | added | Vladimir Lysikov | Then I believe it will be diagonal in the basis $(1, \alpha i, \beta i, -\alpha\beta)$ where $\alpha, \beta = \pm 1$ | |
| Sep 6, 2024 at 14:39 | comment | added | Sajjad | Assuming $a = e$ and $c = f$, how that matrix will be also simplified? | |
| Sep 6, 2024 at 9:49 | comment | added | Vladimir Lysikov | No, for this we would need $a = e$ and $c = f$. | |
| Sep 6, 2024 at 9:44 | comment | added | Sajjad | I think the last equation is block diagonal matrix where each block has same structure of the main matrix, can it also be simplified to have diagonal matrix ? | |
| Sep 6, 2024 at 9:41 | comment | added | Sajjad | Thank you so much, I will try to generalize that suggestions for bigger matrices with same structure, and feedback you | |
| Sep 6, 2024 at 9:40 | vote | accept | Sajjad | ||
| Sep 6, 2024 at 8:43 | history | edited | Rócherz | CC BY-SA 4.0 | Changed one word |
| Sep 6, 2024 at 8:14 | comment | added | Vladimir Lysikov | I edited so that it works for complex numbers. | |
| Sep 6, 2024 at 8:13 | history | edited | Vladimir Lysikov | CC BY-SA 4.0 | added 141 characters in body |
| Sep 6, 2024 at 7:37 | comment | added | Sajjad | What's about if the matrix $A$ has complex values? Sorry, I forgot to mention that matrix $A$ has complex values. | |
| Sep 6, 2024 at 7:13 | history | edited | Vladimir Lysikov | CC BY-SA 4.0 | edited body |
| Sep 6, 2024 at 6:57 | history | answered | Vladimir Lysikov | CC BY-SA 4.0 |