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The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region.

In method $(2)$ When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

enter image description here

In method $(1)$ you take a circular region, and use another cylinder for bounds. enter image description here

The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region.

In method $(2)$ When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

enter image description here

The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region.

In method $(2)$ When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

enter image description here

In method $(1)$ you take a circular region, and use another cylinder for bounds. enter image description here

added 81 characters in body
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S L
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The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region.

In method $(2)$ When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

And I prefer the method $(2)$.enter image description here

The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region. When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

And I prefer the method $(2)$.

The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region.

In method $(2)$ When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

enter image description here

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S L
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The first totwo $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circlecircular region. When you intersect two cylinders, you get a square region as in the link.

enter image description hereenter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

And I prefer the method $(2)$.

The first to $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circle. When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region.

The first two $\iint$ represent your region of integration here you are using $\displaystyle \int_{-1}^{1} \int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}} $ this is a very well known region, it's circular region. When you intersect two cylinders, you get a square region as in the link.

enter image description here

The also note that the height function of this intersection of cylinders are different on different regions, as one cylinder's height is taller than other on some region. On region $(a)$ cylinder $(2)$ is taller than cylinder $(1)$ therefore cylinder $(1)$ acts are bounds for floor and ceiling.

And I prefer the method $(2)$.

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