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Aug 28, 2014 at 19:52 comment added Somnium I even failed to prove that form with 5 radicals do not exist - not enough memory.
Aug 28, 2014 at 12:07 comment added Oleg567 @Somnium, yes, I think it must be huge work. Each next $a_j$ is product of $2$ in high powers. And search can be (maybe) simplified if use alternative form of nested radicals: $$\sqrt{14+\sqrt{140+\sqrt{4096+\sqrt{8847360}}}} = \sqrt{14+2\sqrt{35+4\sqrt{16+3\sqrt{15}}}},$$ $$\sqrt{32+\sqrt{672+\sqrt{229824+\sqrt{11943936000}}}} = \sqrt{32+2\sqrt{168+6\sqrt{399+60\sqrt{10}}}}.$$
Aug 28, 2014 at 8:15 comment added Somnium Just letting you know, I can prove that $3+\sqrt{2}+\sqrt{3}+\sqrt{5}$ can't be represented with 4 or less nested radicals. So I will try to find it with 8 roots, however numbers will be so big, that I don't know if my computer will find solution in reasonable time.
Aug 28, 2014 at 6:33 history bounty awarded Somnium
Aug 27, 2014 at 22:20 history answered Oleg567 CC BY-SA 3.0