Timeline for Why is $i^2$ equal to $-1$?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 18, 2014 at 4:53 | comment | added | imranfat | This is not only black magic. (+1)The way how Jamil used the rule for square root multiplication with negative radicants is simply false! | |
| Oct 18, 2014 at 4:11 | comment | added | user109879 | There's some black magic there. It's not true in general that $\sqrt{a}\sqrt{b} = \sqrt{ab}$, unless you select a branch. For example, you could do $-1 = \sqrt{-1}\sqrt{-1} = \sqrt{1} = 1$ if you are not careful. | |
| Oct 18, 2014 at 4:05 | history | answered | Jamil_V | CC BY-SA 3.0 |