0
$\begingroup$

My Exercise Problem:

Let x1, x2, ..., x7 be observations of independent random variables X1, X2, ..., X7 with E(Xi) = μ and Var(Xi) = σ2, for all i = 1, 2, ..., 7.
Let σ2obs = $c(x_2^2 + x_6^2- \frac{(x_1 + x_7)^2}{2})$ be a point estimation of σ2.
Determine the constant c such that σ2obs becomes a unbiased estimator of variance.

The correct solution:
c = 1

What I need help with
How do I solve this problem? I am very new to point estimations and "unbiased estimators of variance and standard deviations". I want to gradually become better at solving these type of questions, where should I start? Perhaps it would be good for me to start with similar problems but on a easier level, any advice where I can find such problems?

$\endgroup$

1 Answer 1

1
$\begingroup$

Considering that $E(X^2)=V(X)+E^2(X)$ and setting

$$T=X_2^2+X_6^2-\frac{(X_1+X_7)^2}{2}$$

You get that

$$E(T)=2(\sigma^2+\mu^2)-\frac{1}{2}(2\sigma^2+4\mu^2)=\dots=\sigma^2$$

Thus T (your original estimator with $c=1$) is unbiased of variance, as requested

$\endgroup$
4
  • $\begingroup$ How did you get $$E(T)=2(\sigma^2+\mu^2)-\frac{1}{2}(2\sigma^2+4\mu^2)$$ ? :) $\endgroup$ Commented Aug 9, 2021 at 18:20
  • $\begingroup$ @AugustJelemson : $$E(T)=E(X_2^2)+E(X_6^2)-\frac{1}{2}E[(X_1+X_7)^2]$$ and so on...by the way did you forget to accept my answer? $\endgroup$ Commented Aug 9, 2021 at 20:53
  • $\begingroup$ $E(X^2)=V(X)+E^2(X)$ is this a well known theorem/definition that I should know? :) When can I apply this? $\endgroup$ Commented Aug 10, 2021 at 8:52
  • $\begingroup$ @August Jelemson : like in this case when you have to derive second Moment given variance and mean. In this case any $X_i$ have the same mean $\mu$ and variance $\sigma^2$ $\endgroup$ Commented Aug 10, 2021 at 9:15

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.